Scheme syntax

procedure: cons obj1 obj2

Returns a newly allocated pair whose car is obj1 and whose cdr is obj2. The pair is guaranteed to be different (in the sense of eqv?) from every previously existing object.

(cons 'a '()) => (a) (cons '(a) '(b c d)) => ((a) b c d) (cons "a" '(b c)) => ("a" b c) (cons 'a 3) => (a . 3) (cons '(a b) 'c) => ((a b) . c)

Ways of defining various expressions:

(begin (foo) (bar)) is a scheme expression that will run each subsequent expression within the () of begin, and returns the evaluation of the last expression.